There is magic number containing nine different digits 1,2,3,4,5,6,7,8,9 (not in order).
The total nine digit number is divisible by 9.
If the rightest digit is omitted then the new 8-digit number is divisible by 8.
If the rightest digit is omitted then the new 7-digit number is divisible by 7.
If the rightest digit is omitted then the new 6-digit number is divisible by 6.
and so on...
But the last number is of-course divisible by 1 and also by 3.Tell the original nine-digit magic number.
question no 2
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answering by steps
i am answering by steps...finding for anyone with the total....
THE LEFTMOST NUMBER IS 3
THE LEFTMOST NUMBER IS 3
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